Java Basic(82)-Exception Handling

import java.util.*;

public class sample {

public static void main(String[] args){

Scanner input = new Scanner(System.in);

int x = 1;

do{ →重複循環

try{

System.out.println("Enter first num: ");

int n1 = input.nextInt();

System.out.println("Enter second num: ");

int n2 = input.nextInt();

int sum = n1/n2;

System.out.println(sum);

x=2;

}

catch(Exception e){

System.out.println("You cant do that");

}

}while(x==1); → 當x==1;

}

}

程序將運行，直到您輸入正確的整數：

Enter first num:

43

Enter second num:

0

You cant do that

Enter first num:

40

Enter second num:

10

4